x+12/7x^2-28

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Solution for x+12/7x^2-28 equation: 


x in (-oo:+oo)

(12/7)*x^2+x-28 = 0

12/7*x^2+x-28 = 0

DELTA = 1^2-(-28*12/7*4)

DELTA = 193

DELTA > 0

x = (193^(1/2)-1)/(12/7*2) or x = (-193^(1/2)-1)/(12/7*2)

x = 7/24*(193^(1/2)-1) or x = -7/24*(193^(1/2)+1)

x in { -7/24*(193^(1/2)+1), 7/24*(193^(1/2)-1) }

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